Maxwell Boltzmann Distribution Function

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  1. Tonya Coffey
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Комментарии
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This was yet another really rad presentation. Thank you!

Shackled
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Great job. Very very transmitive/transmitative* as a lecturer. (* no such words exist for <communicable>). On the way to check Black Body.

georgevendras
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Hmm, a question on the final example please. 4.86eV/k = ΔΤ = 56125Kelvin. Or for those who prefer, 4.86eV = kT = hf => f = 4.86/h = 1.17*10^15 -> 255.11nm of photon or "electromagnetic wave of short duration" or whatever you like to call a photon. That is, we need to apply heat of temperature 56125Kelvin so that one atom goes from ground to 1st excited state. So, under this perspective, and thinking classically, there is no way for a mercury atom to escape the boiling surface of the (let us say) casserole. But you say here that 49700 atoms will escape. Does this has to do with any quantum tunneling effect (extremely low possibility to overpass the Udynamic barrier)??? Are we allowed to think that tunneling effect occurs here?

georgevendras
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Very, very confusing to keep telling your students that the ratio of two probabilities is a probability. Dear o dear.

jacobvandijk