Python Coding - Asking User's Questions

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Learn how to ask your user's questions in Python using the "input" feature.

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Great tutorial, learned something today and got everything right and even managed to add a few inputs which worked. thanks, mate!!

RobertoJrd
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Curly brace formatting seems like it would be more efficient, i still learned from this video though keep them coming man!

brandonruiz
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Dude you can tell his aussie because of the crows in the background.

jeffkidney
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nice video plz make more video on python

raunikrai
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Print("This really helped me, thank you", name, "I will subscribe")

sadblue
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Design a data structures for handling student records - designing a solution, implementation (using basic DS)

keerthantk
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letter= '''dear <NAME>
YOU ARE SELECTED!
DATE= <DATE>
'''
a=input("enter your name")
b=input("enter the date")
c=letter.replace("<NAME>", a)
c=letter.replace("<DATE>", b)
print(c)

sir, in this code name can't be replaced, please tell me the solution

artisthindustani
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It's not working for me, it says some weird stuff and doesn't do a thing

Pies.
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typed in the same code and for some reason is a string error

juststeven
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Hi.. I am new to programming, I started to learn python, I have downloaded VS code and Pycharm IDE to run python, my normal code is running successfully but when I define any function in the code, it does not show any output(does not show any error either). Please help me how can I resolve this. Thanks alot

deepshikhagupta
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HI, how to filter-out columns record value using python. For example the column name is HC71. It have 10873 records. the record values are -119, -443, -164, 300, 250, 50, -200, 200, ...etc. I want to give value >=200 "over", -200 up to 199 "mild", <-200 "under"

asmareadane
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how do i make it so it has 2 answers for example in my class im doing a menu
the question is what would you like green milk or blue milk
how would i make it so whatever answer they give out of the 2 it comes up with something like
ok and what else would you like

victor-xlmf
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if per>=60:
print("first divison", per)
else:
if per<60 & per>=45:
print("second divison", per)
else:
if per<45 & per>=33:
print("third divison", per)
else:
print("fail", per)

is this code is rigt or wrong

officedhar
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7:21 it gave me "name" as "invalid syntax" as SyntaxError Message

dkiem
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you could of used an f function for the print part

trumpgaming
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I did exactly what you did and got a EOF error

cortlandstrait
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You can simply define a function, I guess.

stanislavdimitrov
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Yeah straight up didn't work. Followed exactly

hockeydude
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i did everything and i got a string error :P

russtycrussty
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well d'day mate!! throw another shrimp ion the barbie.. etc

chescarino
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