math YouTuber fails

Math, but fast!
#math #algebra #calculus #trig

[cyrusyeung]

Translation:
不行欸 = It doesn't work

[issamzreik]

I think that you can just add and subtract 2 from the numerator and it becomes 1-[2/(2+e^(1/x))] and the answer is 1

[vladimirrodriguez]

That quotient is of the type inf/inf, so aplying L'hôpital's theorem it results: lim -e^(1/x)/x^2/(-e^(1/x)/x^2)=1

[anonymouscheesepie]

it’s 1 just by looks
if we let some u = 1/x then the limit becomes the limit as u approaches infinity of e^u/(2 + e^u). we know that constants don’t affect the end behavior of functions at infinity so it becomes the limit as u approaches infinity of e^u/e^u which is of course 1.

[Anmol_Sinha]

Divide the numerator and denominator with e^1/x and you would get 1 as
2/e^1/x = 2/inf which approaches 0
And the limit will just be 1/1 =1

[xtxnobody_coll]

It infinite/infinity form which is indeterminant form so use L'hopital rule- Differtiate numerator and denominator which gives e^1/x /e^1/x so the answer is 1😮.

[Dantido]

Since the two will become a negligible, shrinking percentage of difference between numerator and denominator, and due to the definition of a limit, said fraction will become 1.

[rexomath]

BPRP = Biological personal reliability program 🥴👉🏻👈🏻