CAT 2019 SLOT 1 Solutions Quantitative Aptitude | Geometry | Question and Answer

#cat2019
In a circle of radius 11 cm, CD is a diameter and AB is a chord of length 20.5 cm. If AB and CD intersect at a point E inside the circle and CE has length 7 cm, then the difference of the lengths of BE and AE, in cm, is
A) 1.5
B) 3.5
C) 0.5
D) 2.5

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Best wishes for CAT preparation.

[ronakchatterjee]

Sir we can also use (a-b) ^2=(a+b) ^2-4ab
Here (AE+BE) ^2= 420.25 and 4(AE×BE)=420
Therefore |BE-AE|=√0.25=0.5