The diagonals of a parallelogram ABCD intersect at O. If \( \angle \mathrm{BOC}=90^{\circ} \) an...

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The diagonals of a parallelogram ABCD intersect at O. If \( \angle \mathrm{BOC}=90^{\circ} \) and \( \angle \mathrm{BDC}=50^{\circ} \). then \( \angle \mathrm{OAB}= \)
a. \( 40^{\circ} \)
b. \( 50^{\circ} \)
c. \( 10^{\circ} \)
d. \( 90^{\circ} \)
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