🔺19 - Moment of a Couple 2D: Example 1 - 3

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🔺19 - Moment of a Couple 2D: Example 1 - 3

In this video we are going to learn how to determine the moment of a couple in a 2 dimensional space

A couple is defined as two parallel forces having the same magnitude but opposite direction and separated by a perpendicular distance d.
The moment of a couple is called couple moment and it is given by
Mc = Fd, where
F = the magnitude of one of the force and d = is the perpendicular distance between the two forces.

Equivalent Couples: Two couples are said to be equivalent if they produce a moment with the same magnitude and direction.
thus
F1d1 = F2d2

Resultant Couple Moment: Given more than one couple,
the Mcr = F1d1 + F2d2 + Fndn....

We shall solve three examples in this video.

00:00 - Moment of a Couple
02:20 - Equivalent Couple
04:11 - Resultant Couple
05:31 - Example 1
08:26 - Example 2
11:14 - Example 3

Playlists on various Course
1. Applied Electricity

2. Linear Algebra / Math 151

3. Basic Mechanics

4. Calculus with Analysis / Calculus 1 / Math 152

Make sure to watch till the end.
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Thank you.
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You're too good i understood this in 16 mins❤

desmondpila
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this is my solution of using moment of a couple anticlockwise:

Mc = 0 anticlockwise
Mc = 400(2) -200(0.2) - 300(5)
Mc = -740 N/m clockwise

is this considered as a correct answer?

wangyi
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For question 1, why would the horizontal forces matter? Since they pass through the line of action they shouldn’t matter right

elvapeh
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isnt a clockwise rotation of a moment (-) while a clockwise rotation (+)?

tiikis
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Isnt the ccw (+) and cw(_) why did u made it positive sir?

evansyuri
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hi, i still do not get when it is clockwise and when it is anticlock. hope u will see this.

АдемаАбдрахманова
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I think the -2.6 is wrong I think it is -3.5

charlespranciliso