C++ Tutorial | Part 31 | Input validation! (cin wrong input error-check)

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[Matice]

Finally someone who can explain well and not mouth breathe so much! thank you

[zelotypia]

JESUS CHRIST, I have been puzzled by this for so long and ignored it until now but couldn't handle not knowing how to do it anymore. Just saved me a huge headache, thank you!

[alfredopozos]

BLESS YOUR SOUL JUST KNOWING THAT I COULD DO "== false" HELPED ME SOLVE MY LAB. THANK YOU. DEF SUBSCRIBED AND LIKED

[islandwoodfired]

14:39 "gotta do a bunch of shit..." sounds about right...lol

[tohruoikawa]

God bless you man !
this video is seriously underrated

[guilhermecampos]

Simple and very good solution. Thanks.

[loveandpeace]

you're a thanks sooo mucho, i really mean it, with this u are helping me a lot and i really appreciate it <3 luv u <3

[abuzharrluqman]

IM HERE 2020!!! TQ FOR SHARING THIS!!!!

[amymathews]

Good sir, God bless you. You really helped me out with my project!

[SB-lsqj]

"We try to crash everything, go crazy apeshit--"
lmao

[PontusOzzyA]

you have to use "==false" for it to work, at least for me and another dude in the comment section. thx.

[latronix-omnigenus]

Actually setw(1) isn’t doing anything in your code. It’s working because of flushing cin (clear & ignore). Setw is not a good implementation because an app might ask the user for arbitrary numbers, so setting it to a specific width is not good.


You cin.clear() to unset the failbit (so you no longer get cin.fail() == true or !cin.good as true in your case). The proper way to do cin.ignore now is like: cin.ignore(std::numeric_limits<int>::max(), ‘\n’)


You do have a better alternative, instead of adding clear & ignore after the if statement, you can do this: if (!cin.good() || cin.peek() == ‘ ‘). Peek will check a whitespace. This will force the error if a user types 1(space)2 instead of just assuming that the correct input is 1 and ignoring 2. std::isspace() would not be an option because it also gets the newline.


Your error messages should go in cerr instead of cout.


Do note that my answer is by no means a “great” implementation. Properly sanitizing content and handling input is a very tedious task. You should probably use a library for this or take the input as strings and properly handle it. Also you need to account for locale and Unicode characters.

[luigifan-CyanDestructor]

It was very, very useful! Thanks a lot!

[TJKhara]

Hi Suraj,

This code works really well. Saved me from quite a bit of headache.

Do you think you could go over in a bit more detail was you teach at the end of the video with making the menu with templates so that it is not restricted to any type?

[dillonfleharty]

What if I want it to not allow floating point numbers?

[god-of-creation]

is there a way to not accept string input from a keyboard using a c++ function

[RCPorter]

I used this in a class project and it works for the most part. However, I found that if you are looking for an integer value and the user inputs a floating point it accepts it and then does some craziness in key buffer that caused my program to skip the next input attempt entirely.

[rand]

If I want intger to be only from 1-8 where should I put the condition?

[ARYANKUMAR-yctc]

Sir please help me!
I've coded ifelse statement for my code.
I code if(n=='aryan')
cout<<"Hello\n";
else(
cout<<"Byy"
)

But when I running program it always interpret else not condition. And program is showing that variable type is too long for variable n.
Please help me!

[kamilosok]

Can you make video about input validation in classes?