6. Dictionaries in Python for Class 12 Boards | Class 11th Revision

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L = [ ]
for i in range(100):
if (i%3==0 and i%5==0):
L.append(i)
print(L)
We can also use (i%15==0) as the 'if' condition.

vedantdev

The problem solving logic is too good, amazing!

arjunverma

APNI KAKSHA
BEST EDUCATIONAL CHANNEL🙏🏻🙏🏻
Who

amitsinghkushwah

Please complete this python course very soon, preboards are near😰😰😰😰😰😰

vatsalsharma

19:20 we will have to take it as I in range (7) as we need to print only 9 elements.
2 elements taken initially + 7 elements from loop as it will go from 0 to 6

anonymous-yqpi

L=[]
for d in range(101):
L.append(d)

L2=[]
for i in L:
if i%3==0 or i%5==0 and i<100:
L2.append(i)
print(L2)
This is anwer of HW question. Is it usefull?

prince.

Bhaiya plz add more questions on programs in videos which important for boards and thanks for providing that much ausome lectures

AbhishekSharma-wtst

H.W. Question :
L=[]
for i in range(100):
if ((i%3==0) and (i%5==0)):
L.append(i)
print(L)

manavgusain

Jaldi complete karaye ye series bhaiya🙏🙏🙏🙏🙏

vibhashkumar

a=[]
for i in range(1, 101):
if i%3==0 or i%5==0:
a.append(i)
print(a)
hw done
😁

sainikaindorjey

Solution to HW:

L = []
for i in range(1, 101):
if i%3 == 0 or i%5 == 0:
L.append(i)
else:
continue
print(L)

abhayzz

Thanks a lot waiting for chemistry organic..

factsmyths

16:27 max= len(L[0]), then value of max can be compared to the length of other elements

tusharrocks

thanks a lot to the entire team of apni everything easily❤

prachi

7:44 increase volume and put your headphones on

yashrajput

1hrs later my cs board exam and I'm watching this😂

sahilnegi

hw ques answer
L=[]
for i in range(1, 101):
if(i%3==0 or i%5==0):
L.append(i)
else:
print(i)

tusharsingh

Thank you so much for this python course ❤️... can you please help us out with the SQL part too?

vedikasingh

Bhaia thanks for the series, , , , it is amazing, it clears each concept
I am proud to be born in this Era of internet where I can learn as much as I wish

indianvines

HOMEWORK:

a=[]
for i in range(1, 101):
if i%3==0 or i%5==0:
a.append(i)
print(a)

DialShubhra

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