Intermediate Algorithm Scripting - Sum All Numbers in a Range - Free Code Camp

[lanremufu]

Math.min and Math.max did it! Thanks for the great content

[RelaxingMusic-dpnv]

Hey!, a great tip I am a Junior developer who is learning a lot from your video tutorials and I would like to learn how to use the 'Node' option, Thanks a lot brother

[cosmelvillalobos]

great explanation man, thanks for the great content.

[zken]

Wonderful lesson Mr. Ian I thank you for going deeper into this lesson. I didn't use Atom I am using that which is called TypeScript, however, I will be getting and using Atom it won't hurt to use other applications as I see it.
function sumAll(arr) {
let minimumNumber = Math.min(arr[0], arr[1]);
let maximumNumber = Math.max(arr[0], arr[1]);
var result = 0;
for (var i = minimumNumber; i <= maximumNumber; i += 1) {
result += i;
}
return result;
}
console.log(sumAll([1, 4]));

[mitovlz]

Thank you fantastic explanation, it would be great if you do a tutorial about install and use node.

[cleaningbad]

thanks a lot for the atom explanation!

[athidlambulo]

How to calculate sum of the numbers up until the index point using recursion?

[lukamihelac]

Thank you for you explanations!! I just wanted to ask, how to do get those "code recommendations" in browser, because when you write code in freecodeacademy it looks the same as if you were writing in VScode?

[scottldn]

"a loop makes more sense 'cos recursion is annoying" 😂

[madalinsion]

Thank you for the explanation. I have a question if you would be so kind to help me with.
If I understood correctly the arr[0] and arr[1] from Math.min(arr[0], arr[1]); are referring to the position in the arr first and second. But what If we would not know the length of the arr how would we find the min/max then?
Would we first have to find out the length of the arr and fill it to ...arr[x] or is there an easier way?
Thank you in advance!

[minhhieu]

Hello, i want to share my simple solution to this problem using a little bit knowledge about math:

function sumAll(arr) {
return
}

sumAll([1, 4]); //it will pass the test.

[icaruz]

//MY SOLUTION WITHOUT BUILT IN

function sumAll(arr) {
let min = arr[0];
let max = arr[1];
let sum = 0;

if (max > min) {
for(let i = min; i <= max; i++) {
sum += i;
}
return sum;
} else if (min > max) {
for(let i = max; i <= min; i++) {
sum += i;
}
return sum;
}
}
sumAll([1, 4]);

[freecodecampdeveloper]

Thank you Ian for the excellent videos, been watching for a while now and your explanations are great! Are you on Twitter?

[freecodecampdeveloper]

function sumAll(arr) {

const minNum = Math.min(arr[0], arr[1]);
console.log(minNum);

const maxNum = Math.max(arr[0], arr[1]);
console.log(maxNum);

let endResult = 0;

for (var i = minNum; i <= maxNum; i++) {
endResult += i;
}

return endResult;
}

sumAll([1, 4]);