Let A, B, C, D be (not necessarily square) real matrices such that `A^T=BCD: B^T=CDA; C^T=DAB

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I. `S^3=S`
II. `S^2=S^4`
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But, S transpose=S because S=ABCD=D transpose × D . As, multiplication of a matrix with its transpose is always symmetric so, my previous statement was correct . S transpose = S³(as you have proved), so, S transpose= S = S³, so multiplying by S on both sides we get S²= S⁴, so both statements are correct should be the answer, please verify mam

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