write a java program to find second largest element in the array in the java

#learnwithkrishnasandeep #javacodinginterviewquestions #javaexamples #javaprograms #javatutorials #javaprogramming This tutorial explains how to find second largest element in array in java.

[kartiktyagi]

what if there is a repetition of the highest element in the array then it will print the highest element only

[deependrasingh]

what if this situation comes -
int arr[ ] = {1, 2, 3, 4, 5, 6, 6};
please answer.
thank you!

[swathik]

Thanks bro.I understood ur explanation simply.thankd a lot

[GauravSharma-eief]

Wow So simple....some more programs pls

[digvijaysingh]

we can sort the array using bubble sort algorithm which is the simplest one if you dont want to use sort function

[LalitKumar-cwrf]

love you bro good content made it really easy for understing

[SmartProgramming]

nice one but there is another method of finding second largest number by taking two variables and that is much better then this method, anyways good going, keep it up sir, thank you 🙂🙂🙂🙂👍👍👍

[tanujkumar]

without using sort() method or any in-built function

[Akhil]

with out taking values initially how can we solve ?

[vishwaprasad]

Hi,

If we don't know the position then how will be the approach.

for ex: we take value as desired.

Regards,
Vishwaa.

[apurbapradhan]

public class MyClass {
public static void main(String args[]) {
int arr[]={4, 2, 1, 5, 3};
int sl, l;
l=sl=Integer.MIN_VALUE;
for(int i=0;i<arr.length;i++)
{
if(l<arr[i])
{
sl=l;
l=arr[i];
}
else if(arr[i]>sl && arr[i]<l)
{
sl=arr[i];
}
}
if(sl==l)
{
System.out.println("There is no 2nd largest number");
}
else
{
System.out.println("The highest number is "+l+"The 2nd largest number is "+sl);
}
}
}

[mudasir]

package PracticeJava;

public class SecondHighestNumber {

public static void main(String[] args) {
// TODO Auto-generated method stub

int num[]= {23, 45, 2, 4, 11, 63, 32, 0, 4, 55, 50, 89, 57};
SecondHighestNum(num);


}

public static void SecondHighestNum(int num[])
{
int result =0;

for(int i=0;i<num.length;i++)
{
for(int j=1;j<(num.length);j++)
{
if(num[j-1]>num[j]) {

result=num[j-1];
num[j-1]=num[j];
num[j]=result;
}
}

}

}

}

[soudiptadutta]

To find second largest element in array in java we can use SortedSet.
Here is the complete solution.

import java.util.SortedSet;
import java.util.TreeSet;

public class Abc1 {
public static void main(String[] args) {

int[] a = { 1, 5, 4, 2, 8, 1, 8, 9, 9, 100, 23, 66, 99 };
SortedSet<Integer> set = new TreeSet<Integer>();
for (int i: a) {
set.add(i);
}
System.out.println("set => " +set);
// Remove the maximum value; print the largest remaining item
set.remove(set.last());

System.out.println("second largest after removing the largest => " + set.last() );

}
}

[ShivKumar-yvti]

if we have duplicated number for ex{2, 5, 6, 9, 9, 9};

[aayushjoshi]

this code will fail if there are repeated characters, in such cases we need a set to filter data, here is the code public static void main(String[] args) {
int arr[] = { 1, 2, 3, 4, 5, 7, 6, 6, 7 };
Set<Integer> set = new TreeSet<>();
for (Integer integer : arr) {
set.add(integer);
}
Integer[] array = set.toArray(new Integer[set.size()]);
int secondLargest = array[array.length - 2];

}