[October SAT Math] These 3 Questions were JUST added

What’s going on y’all 🤙

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FAQ
Name: John
Where did you study - Emory University
What did you major in - Economics & Psychology
How long have you been teaching - Since 2012
Why do you decide to teach - It was tough for me to figure it all out when I was in high school, and my goal is to make it a lot easier for current students
Can you make videos on Reading & Writing - I don’t know those sections well enough to talk about them.
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[winterwind-jkfm]

for circle questions like those, you can also just plug the entire equation into desmos and find out if any of the x values in the choices fall within the circle

[mathster]

For the circle question at 0:59, since they're only asking for the X-Coordinate, you could do -4 (X-coordinate of the center) ± 11 (radius, square root of the right side of the equation), and get that the X-Coordinate must be from -15 to 7, which only answer B fulfills.

[RisetotheEquation]

For the first one you literally enter the equation in desmos, then type in a moveable point like this: (answer choice, b) and move the point up and down with the slider for b until you can tell it intersects the circle. Clearly happens with (-14, b). This took me 15 seconds with zero risk of making a calculation blunder. Amazing how tutors these days barely lift a finger to teach students how to operate the greatest gift the college board ever provided on the SAT math.

[abdelrahmanhazem]

An alternative method for the first question. The radius of the circle is 11, and the center of the circle is ( -4, 19). Hence by adding and subtracting the radius from -4, we can find the maximum and minimum values of a which will turn out to be 7 and -15 respectively. And only -14 lies within those values. P.S. drawing a quick sketch makes it much easier to understand.

[RisetotheEquation]

Here we go again...for the third problem just enter a single point into a table in desmos, namely (5, -4) since that is given on line t. Then calculate the slope between the two points with desmos by doing (1 - - 4) / (-1 -5), which is -5/6. Line t must have slope 6/5 since tangents are perp. to radii. Then do a regression to get the line graphed for you by doing y_1 ~ 6/5 * x_1 + b. Then drag your mouse along the line until you find an answer choice on the line. Clearly at (10, 2). This took about 1 minute.

[itsanonymous]

For the second question, it is also easy to do it by using the concept of sum and product of roots, since the roots of the equation are given in the graph (-3 and 1)

[RisetotheEquation]

For the second one you just enter a table in desmos and plug in three obvious points from the graph: (-1, -8), (-3, 0), and (1, 0). Then do a regression to have desmos solve for the missing constants b and c by typing y_1 ~ 2x_1^2 + bx_1 + c, then in the next line type bc and your answer (-24) is handed to you in less than 30 seconds with zero chance of making a calculation error.

[rishikaradakal]

For the second question, you can use the sum of roots and product of roots formula. Sum of roots is -b/a, and product of roots is c/a, so you just find the sum of the roots which is -2, and the product of the roots which is -3. Then you plug it into the formula. -b/2 has to equal -2, so b is 4. And c/-2 has to equal -3, so c is 6. Then you just multiply to get your answer of -24.

[khoata]

for the first question (22), it would be much simpler and time-saving to just throw the circle equation into desmos and check for the possible x-intercepts.

[jwmathtutoring]

All 3 questions can be done fairly quickly in Desmos although the 3rd is not quite as intuitive. However, the first 2 are very easy and can be done in under 30 secs. No reason to spend 2-4 mins doing all the work by hand esp on #1.

[Andrew-Tsegaye]

Where have you been John come on we need you... You're our brother this family mustn't be lost ❤ more vids more..

[johndemartin]

Question 1 is a head-solver (no plugging in, no Desmos). Circle has a center at (-4, 19) and a radius of 11. Therefore, no x-value can be less than -4 - 11 or greater than -4 + 11. Only -14 (choice B) satisfies

[brando]

For the last question I think using point slope form would be better. If you like only having y on the left then u can simply add over the y1 so u get y = m(x-x1) + y1. It makes it a lot easier bc then u can plug it into desmos as a function without needing to solve for b

[baborsregime]

for the first question, input the equation in desmos. just visualize yourself which point can be inside the circle. No need to go through any calculation.

[abdullah_abisola]

I enjoyed your solution to the 2nd Problem 7:08

I used Vietta's formula
Sum of Roots/Solutions = -b/a
Product of Roots = c/a
Find c and b and then Multiply

I would have used ur method. Wanted to Try this formula out

[leouladera]

for the graph equestion you can put the values on desmos and use the slider value until you get it right

[itsyoboiasu]

I want to do good but only two weeks are left, I haven’t prepped for my exams and I don’t have time and I don’t want to give it more than once I’d love advice from anyone

[panickdolhpernate]

Ur videos are so helpful, they are thorough and easy to follow!❤ well explained thank u

[TestPrepTutoring]

You can also enter the circle equation into desmos and eyeball it or enter x= -16 which lets you create a slider from -16 to 19 with step 1. Drag the slider around to see which x value actually works. It seems that the digital SAT loves to reinforce that an (x, y) ordered pair satisfies the equation that it is a solution for. Love the way you did the circle question and the way you emphasized the logic. ACT used to include these questions often.

[RazeeOnYt]

taking the test in less than 12 hours wish me luck