OCR MEI Statistics 1 4.12 Permutations and Combinations: An Exam-Style Question

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Firstly a thank you for these video, they are really helpful, are you planning on making any other exam style question videos?

PefectCell
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Could you please help me with this question?

3 men and 7 women have to be seated in two rows with 5 seats each. How many ways can they be arranged if each row has a majority of women?

kimgking
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Would watching and making notes from all the videos from this playlist be enough to prepare for the S1 exam?

thomasmohan
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If You were to use the Binomial distribution instead, Does it work or am i just doing it wrong. Can you explain why i get a different answer. If X is B[(4), (4/13)], i.e Binomial distributed with 4 trials, with a probability of hounds as 4/13. Hence also the probability of no hounds (q) is 9/13. So for P(X >= 3), i.e P(X = 3) + P(X = 4), I got; 4C3 x (4/13)^3 x (9/13) + 4C4 x (4/13)^4 x (9/13)^0 or (2304/28561) + (256 / 28561) = 2560/28561 = 0.089632... = 0.0896 (4.s.f) As my final answer. This however is wrong is seems but i aint sure why.

patrickh
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at 2:10 why do we need to pick one dog that isnt a hound?

bobnob
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What grade do you teach to? Is this content sufficient for an A grade?

thomasmohan