16.2 Arrhenius Equation k1,k2,T1,T2 [HL IB Chemistry]

Changing temps for a reaction will change the rate constant. The equation allows this to be calculated, if you know the 3 of 4 variables (the different rate constants at different temps).

[coklat]

This is very clear . Thank you so much

[Lemonized]

Recently found your videos and they are for sure a great material to revise what took place during the lessons :) The only thing that might cause problem for a fresh student are not-accurately placed dots which were supposed to mean that a number has decimal places. (In reality it looks like you are multiplying two numbers :P)

[dominicphillips]

ln(.50)=-.693? I’m lost as to how you got .901

[jarcho]

If I were searching for more practice problems of this type, what key word would I use? Kinetics?

[heretocomment]

@ibchemvids
Hello Richard, can you explain how you chose which one is k1 and which is k2? I mean, what is the rule for assigning k1 and k2?, not just for this question but in general? Because 10/1 is not the same as 1/10. Will the final answer always be the same no matter which one you assign as k1 and k2? Thanks in advance.

[jessedavis]

Why did you put 1 for K1 and 3 for K2 in the final example? I know K2 is 3x K1 but I did not want to make that assumption.

[sohoyankee]

Hello and thank you for your helpful video. Question, why did you put ln k1/k2. Isn't the equation ln k2/k1?

[yourlocalpastaenthusiast]

Damn, the Math HL kids are really flexing in this comment section

[izzystudies]

Where did you get the value for E(a) from at 3:02?

[joyceldahn]

Am left behind!
How did you got 0.901?

[austink]

Shouuldnt the last question be rounded to 2 sf?

[alicesteffl]

How did you get -0.901 for -lnK2 if the natural log of 50 is 3.91?

[Freddo]

Where did the 3.33 x 10^-3 come from at 4.06?

[Irshadahmad-bvtr]

Can u solve this one
Lnr2/r1=e/R(1/T1-1T2)

[jeanclaude]

t2=311k how did you get to that final answer, when I plug everything in I don't get that.

[flowerchild]

i don't understand how you got to the number you did for t2-t1 at 405

[tanyatodd]

How did u ultimately get rid of ln(50)?

[kristinefedericos]

How do I solve if the only given is T1, T2 and R?

[SaKm]

3:01 doesn't k2 have to be 0.005 since its Twice as fast as k1

If k2 is 0.020 it means it is twice slower than k1 which is 0.010

[johnn.]

AT 5:49 why would it be the ln(.50) - ln(k_2) and not ln(.50)/ln(k_2)??