The Maths Prof: Area of Triangle (Trigonometry 1/2 x ab x sin C)

Learn how to work out the area of a triangle using Sine.
I hope you find the lesson useful! Subscribe to my YouTube channel to stay up to date with new uploads and follow me on Instagram @themathsprof for more maths! :-)

[jabebwell]

Please don't ever take these down. You are SO HELPFUL!!!! Thank you so much!

[ejerciciosdeFabi]

In the last example the value she obtains corresponds to the one with the calculator in Radians. The correct answer is 8.03 to 3s.f.

[sbahlekhoza]

Watching this video 2021 and it so helpful . thank you so much for not deleting this video 💕

[NiTrXeDitz]

this video is very helpful, i love the positivity please keep uploading about different topics in maths, thanks alot

[TigaBonney]

Thankyou!! So much for not deleting this video it help me alot 😊you the best❤

[Jay-zi]

Im left with 3 months to write my o level exams and this pretty helpful

[QueneechilogracePalmaria-pxoe]

I like u po how you teach madali Lang Ako Maka intindi thank you po

[Alaia]

Thank you so much I was so so confused about diff formula for triangle but now I understand where to use formula.

[ronaalicereji]

Hii!!
I was wondering if you could post videos on 3D trigonometry .
It would be really helpful.
Thank youu!!

[alvinjarolimek]

I like your presentation. If you use the formula : sine squared + cosine squared = 1, we can substitute the equality of the square root of the sine squared of the particular equation mentioned and substitute it into your formula, 1/2 ab sine C. We then use the Law of Cosines and substitute its formula into the formula we discovered. By further calculations we discover a new formula for the area of a triangular. The new formula is unique in its properness. Although you no longer need to know any angles by an entangled knowledge of the values of the sides we produce an area of a triangle. (See 1 John 5:5)

[nambam]

80 divided by sin60 is a negative value, and you cannot square root a negative to find x, this triangle does not exist.

[johnboy]

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