Calculating the pH of a Resulting Solution - Neutralisation Reaction

Calculating the pH of the resulting solution when Hydrochloric Acid is mixed with Sodium Hydroxide. Calculating which solute is in excess and how much of the excess reagent is remaining after neutralisation has occurred.

From this we then were able to use the equilibrium constant for water to determine the concentration of hydrogen ions were remaining in solution and then from that calculate the resultant pH of the solution.

I hope the example helps :)

[kattiper]

I dont gwt one thing, there are multiple values of the same concentration and the rule for concentration of OH- is 10 power 14+ph, and ph is 14+log conc of oh- but here these rules are lost

[swamynarasimha]

Excellent explanation Mr Harold 👌, Thank you for your Video’s

[kattiper]

Great video but maybe next time u could type faster with a keyboard than a handwriting

[goodnessgracious]

1.189E-5 - 3.794E-6 should be 8.096E-6

[amiseelan]

What if  the  RATIO of the reactants  are  1: 2?  Will there be any difference in calculating the pH? So far I've came across a lot of questions with reactants ratio (1 : 2)